Group objects in the mass

[kalyn]

There's a set of objects. It's necessary. group by name and add the keys, If the name matches. I made a flag that filters repetition. I can't figure out how to sum it up.

Dano:

[{
    name: 'aaa',
    coin: 30
},
{
    name: 'bbb',
    coin: 32
},
{
    name: 'aaa',
    coin: 20
},
{
    name: 'aaa',
    coin: 50
}]

The result shall be:

[{name: 'aaa', coin: 100}, {name: 'bbb', coin: 32}]

My code is:

const arr = [{
    name: 'aaa',
    price: 30
},
{
    name: 'bbb',
    price: 32
},
{
    name: 'aaa',
    price: 20
},
{
    name: 'aaa',
    price: 50
}];
const myFunction = (arr) => {
let result = [];
arr.forEach(object => {

let flag = false;

result.forEach((objectResult, index) => {

if (object.name === objectResult.name){

flag = true;

}

});

if (!flag) result.push(object);

});

return result; };

const test = myFunction(arr); console.log(test);

[rosemadder]

You can.

We're going down the range with help. .reduce() with an initial battery as an empty object. We'll check on terations if our battery has a key equal to that. name♪ If not, we'll create a key with an initial value. { name: name, coin: 0 }♪ Verification and creation can be reduced to one step with assistance https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Logical_nullish_assignment ♪ Now we can add value. coin in this facility. At the end, we'll only be able to turn the battery into a set of objects with a bag with help. Object.values()♪

const array = [{
    name: 'aaa',
    coin: 30
},
{
    name: 'bbb',
    coin: 32
},
{
    name: 'aaa',
    coin: 20
},
{
    name: 'aaa',
    coin: 50
}];
const array2 = Object.values(array.reduce(

(acc, { name, coin }) => {

acc[name] ??= { name, coin: 0 };

acc[name].coin += coin;

return acc;

},

{},

));
console.log(array2);