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How to check the word

E
emerson last edited by

I'm writing a bot on my Vk account. There was a need to check reports for proscribed words, such as the prohibited word Arbuz, a proposal that needed to be found: I love the watermelon.
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Analeea

bad_words = ['арбуз']
message = 'Я люблю арбуз'

for word in message.lower().split():
    if word in bad_words:
        print('Обнаружено плохое слово!')
        break

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I think that you can easily fix it with ajax function, you pass as data the input date and php script in which you process the date and do the search will give you the hours available without having to reload the page, I'm not for the call to work when you select the date test with this<input type="date" id="fecha"/> $(function(){ $("#fecha").change(function(){ var valor = $(this).val(); if(valor!=""){ //llamada a la funcion } else { //pass } }) })
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What you want is to do a subset from the bank. In this case you do not need to define a function. The correct command to find the number outliers of a variable var would be:import numpy as np Q1 = np.percentile(df2['var'], 25, interpolation='midpoint') Q3 = np.percentile(df2['var'], 75, interpolation='midpoint') IQR = Q3-Q1 number_outliers = df2[ (df2['var'] < (Q1 - 1.5 * IQR)) | (df2['var'] > (Q3 + 1.5 * IQR))]['var'].size Replicable example:import numpy as np import pandas as pd df2 = pd.DataFrame({'var': [-400, 1, 2, 3, 400], 'B': [5, 6, 7, 8, 9], 'C': ['a', 'b', 'c', 'd', 'e']}) Q1 = np.percentile(df2['var'], 25, interpolation='midpoint') Q3 = np.percentile(df2['var'], 75, interpolation='midpoint') IQR = Q3-Q1 number_outliers = df2[ (df2['var'] < (Q1 - 1.5 * IQR)) | (df2['var'] > (Q3 + 1.5 * IQR))]['var'].size print(number_outliers)
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From the comment:In the text, replace the labels with the missing. In the search line add gaps on the edge of the sentence. ♪ https://ru.stackoverflow.com/users/297727/max Implementation:$search = "как твои дела"; $text = "привет, как твои дела? давай созвонимся."; $text = ' ' . preg_replace("#[[:punct:]]#", ' ', $text) . ' '; if (stripos($text, ' ' . $search . ' ') !== FALSE) { echo 'Найден '.$search; } From the comment:I don't think you're going to have to do that without a regular expression. Something like that. 'b$search\b'. And the code finds everything right. https://ru.stackoverflow.com/users/296878/adokenai Implementation:$search = "как твои дела"; $text = "привет, как твои дела? давай созвонимся."; $pattern = '#\b'.$search.'\b#isu'; if (preg_match($pattern, $text)) { echo 'Найден'; }
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Starting and finishing the line, going in the cycle, the first indicator is increasing, the second down, the numbers are down. We'll change the letters between us that the signs look at. We'll end when the signs match.In the form of a code like that (the truth you didn't say):int j = 0; int k = ch.length-1; while(j<k) { char tmp; if(! Character.isLetter(ch[j])) j++; else if(! Character.isLetter(ch[k])) k--; else { tmp=ch[j]; ch[j]=ch[k]; ch[k]=tmp; j++; k--; } }
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Good friend you have to get the value of input Then make a forEach to iterate the array inconvenientes1 and compare if what the user writes matches some value in the array, if we match the index and assign a new value to the input with the inconvenientes2[index]I hope it helps.Functional example Note: for example is used the javascript library jquery can also be done without problem with javascript vanilla but for quick use jquery.var inconvenientes1 = [ 'BACA', 'LOCA', 'BUEY', 'COLA' ]; var inconvenientes2 = [ 'BACX', 'LOCX', 'BUEX', 'COLX' ]; $("#paterno").keyup(function(){ var valor = $(this).val() inconvenientes1.forEach(function(item,index){ if(item == valor.toUpperCase()){ $("#paterno").val(inconvenientes2[index]) console.log(inconvenientes2[index]) } }) })<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <label for="">Primer apellido</label> <input id="paterno" type="text" name="" value="">
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Find the solution to the problem and share the answer in case someone encounters the same problem: private void DgvDatosReservas_CellContentClick(object sender, DataGridViewCellEventArgs e) { DataGridView DetectarTipoCasilla = (DataGridView)sender; if (DetectarTipoCasilla.Columns[e.ColumnIndex] is DataGridViewCheckBoxColumn && e.RowIndex >= 0) { // invierto el estado del check seleccionado debido a que no se actualiza en el momento de marcarlo. if (dgvDatosReservas.Rows[e.RowIndex].Cells[(int)ENumColDGVDatosReservas.Seleccionar].Value != null) { if (!(bool)dgvDatosReservas.Rows[e.RowIndex].Cells[(int)ENumColDGVDatosReservas.Seleccionar].Value) { dgvDatosReservas.Rows[e.RowIndex].Cells[(int)ENumColDGVDatosReservas.Seleccionar].Style.BackColor = ClsColores.Azul; } else { dgvDatosReservas.Rows[e.RowIndex].Cells[(int)ENumColDGVDatosReservas.Seleccionar].Style.BackColor = ClsColores.GrisOscuroFondo; } } // Metodo que soluciono el problema dgvDatosReservas.ClearSelection(); } } I'm not completely sure why, I probe it since it was solved by giving focus to another cell DataGridView, so I intuit that when cleaning the selection list, update the cells as needed. If the same box is selected (to remove the selection), it does not work to reverse the boolean value of the box check, so I recommend saving the value of that position of row and column, so deter if you select the same and so enter the otherwise line and remove the color to the box (equal can fail if the user clicks repeatedly fast in the box or if you select the same 2 times in a row, it is very rare the behavior of this function of the control). If someone knows how to explain it in more detail, their answer is welcome.
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if ($('#blog').is(':empty')) { $('#blog').html(` <table id="n"> <th>Название</th> <td>Новая занить</td> </table>`); } else { $('#n').html(` <td>Новая запись</td> `); }

How to check the word

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