Calculate two times in a variable in batch
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Is it possible to calculate the difference between two times with the batch and use the response as a variable within the command? The "time" command allows you to make the calculations between initial and final time.
set STARTTIME=%TIME% set ENDTIME=%TIME% set /A DURATION=%ENDTIME%-%STARTTIME%The answer variable (DURATION) returns as an hour: minute:second:millisecond, how do I compare (with the if command) this variable (DURATION) with a predefined time by me within the programming itself? Or do something like that. Example:
if %DURATION% LSS "00:00:01:00" echo Texto.
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The code you are using is this:
@echo off rem Inicio do procedimento. set STARTTIME=%TIME%rem Coloque o procedimento que deseja medir o tempo.
pauserem Fim do procedimento.
set ENDTIME=%TIME%set /A STARTTIME=(1%STARTTIME:~0,2%-100)*360000 + (1%STARTTIME:~3,2%-100)*6000 + (1%STARTTIME:~6,2%-100)*100 + (1%STARTTIME:~9,2%-100)
set /A ENDTIME=(1%ENDTIME:~0,2%-100)*360000 + (1%ENDTIME:~3,2%-100)*6000 + (1%ENDTIME:~6,2%-100)*100 + (1%ENDTIME:~9,2%-100)
set /A DURATION=%ENDTIME%-%STARTTIME%if %ENDTIME% LSS %STARTTIME% set set /A DURATION=%STARTTIME%-%ENDTIME%
set /A DURATIONH=%DURATION% / 360000
set /A DURATIONM=(%DURATION% - %DURATIONH%*360000) / 6000
set /A DURATIONS=(%DURATION% - %DURATIONH%*360000 - %DURATIONM%*6000) / 100
set /A DURATIONHS=(%DURATION% - %DURATIONH%*360000 - %DURATIONM%*6000 - %DURATIONS%*100)if %DURATIONH% LSS 10 set DURATIONH=0%DURATIONH%
if %DURATIONM% LSS 10 set DURATIONM=0%DURATIONM%
if %DURATIONS% LSS 10 set DURATIONS=0%DURATIONS%
if %DURATIONHS% LSS 10 set DURATIONHS=0%DURATIONHS%echo Tempo do procedimento: %DURATIONH%:%DURATIONM%:%DURATIONS%
pause > nul
The variable
%DURATION%stores time in hundredths of second, so to check if it took less than a minute to do the following check:if %DURATION% LSS 6000 (
echo Durou menos que um minuto.
) else (
echo Durou um minuto ou mais.
)
pause > nul
1 second = 100 hundredths of second. 1 minute = 6000 cm.
