cant understand the output of John the ripper
The hash I am trying to break is
279412f945939ba78ce0758d3fd83daa, it's part of a task for learning John. I created a file hash.txt using:
echo -n 279412f945939ba78ce0758d3fd83daa > hash.txt.
Then, I tried running
hashidover it and it gave me md2, md5 and md4 and many more.
So I used,
./john --wordlist=rockyou.txt --format=raw-md4 hashfile.txt
Using default input encoding: UTF-8 Loaded 1 password hash (Raw-MD4 [MD4 256/256 AVX2 8x3]) Warning: no OpenMP support for this hash type, consider --fork=2 Press 'q' or Ctrl-C to abort, almost any other key for status 0g 0:00:00:00 DONE (2021-06-07 05:21) 0g/s 19124Kp/s 19124Kc/s 19124KC/s filimani..clarus Session completed.
Now, when I do:
./john --show hash.txtor
./john --show --format=raw-md4 hash.txtit gives:
0 password hashes cracked, 1 left
Question: What is the meaning of that
filimani..clarus? is it the password? why
--showis not registering it?
johnwith MD4, but that's not a common hash type. MD5 is much more common. My guess is that you didn't try that option for john.
filimani..clarusare the range of words from the wordlist that it is checking.
So, it didn't show the password because it couldn't find the hash
279412f945939ba78ce0758d3fd83daain the wordlist you supplied.