O {}.format("variavel") is the best way. And you can perform calculation and conditions within () kinesis and format the output of {} keys.

First, create a function to read numbers that insists until the user enters something valid:def ler_numero(mensagem, tente_novamente = 'Isso daí não é um número. Tente novamente.'): while True: try: return int(input(mensagem)) except ValueError as e: print(tente_novamente) With makes it easier to do what you want:while True: n1 = ler_numero('Digite o número 1/5: ') n2 = ler_numero('Digite o número 2/5: ') n3 = ler_numero('Digite o número 3/5: ') n4 = ler_numero('Digite o número 4/5: ') n5 = ler_numero('Digite o número 5/5: ') if n1 < n2 and n1 < n3 and n1 < n4 and n1 < n5: print('O menor número é: {}'.format(n1)) elif n2 < n1 and n2 < n3 and n2 < n4 and n2 < n5: print('O menor número é: {}'.format(n2)) elif n3 < n1 and n3 < n2 and n3 < n4 and n3 < n5: print('O menor número é: {}'.format(n3)) elif n4 < n1 and n4 < n2 and n4 < n3 and n4 < n5: print('O menor número é: {}'.format(n4)) elif n5 < n1 and n5 < n2 and n5 < n3 and n5 < n4: print('O menor número é: {}'.format(n5)) if n1 < n2 < n3 < n4 < n5: print('Está em ordem crescente') break else: print('Não está em ordem crescente') break

In C you cannot return a string, because strictly they do not exist. You can return a pointer to a string. You may be thinking so just return a guy char *. This is what everyone finds naively. And there are cases that can work.Works if you allocate memory in heap inside the function, then what function malloc() generating from pointer you return in function and everything works. This is not ideal because you will have to release this memory at some point and the ideal is always to release memory in the same function you create, and you cannot do this just because you need that object to survive longer than the function. Even if not ideal in many cases is the best solution. In others what is done is to allocate in the function that will actually consume the text and there the release is made there, so in this way you do not need to return anything, you just pass by reference what has already been created.If you will do this way you can create only one array of characters in stack. This does not always work well in all cases of real codes, but for small applications it can be ideal. As this code abuses this then it should be the right to do, allocated space in main() and should not return the data in the function, should make this space for use without returning it. When you pass a reference all that is modified in it will reflect on the variable that was passed. It would be something like this:void retornaNome(char nome[], char sobrenome[], char nomeFinal[40]) { https://github.com/maniero/SOpt/blob/master/C/Function/PassString.c .And you will return nothing, you just manipulate nomeFinal Right there.Note that if you try to return an object allocated on stack function when it finishes this object becomes invalid and the best that can happen to you is the breaking application, it can happen worse as running it looks like it's right and one day give a mistake that will not make idea of it and will find that the computer went crazy when actually it's just your wrong code.I could help with some more piece of code but I will not do it because it has many errors in this code, to make sure it would have to rewrite it completely, there are many things there that is not how it is done in C, for example the use of https://pt.stackoverflow.com/q/167528/101 , and has logical errors too. The answer from Isac gives an idea how it is though I think it took an important part of the code, because this seems to be exercise just to manipulate the string in the hand.

The correct and efficient way to do this:using static System.Console; public class Program { public static void Main() { var texto = "0001>0002>0003>0004>0005"; var posicao = -1; for (var i = 0; i < 3; i++) { posicao = texto.IndexOf(">", posicao + 1); if (posicao == -1) break; } if (posicao > -1) texto = texto.Substring(0, posicao); WriteLine(texto); texto = "0001>0002"; posicao = -1; for (var i = 0; i < 3; i++) { posicao = texto.IndexOf(">", posicao + 1); if (posicao == -1) break; } if (posicao > -1) texto = texto.Substring(0, posicao); WriteLine(texto); } } See https://ideone.com/iyIP9q . And https://dotnetfiddle.net/Pq6yZq . Also https://github.com/maniero/SOpt/blob/master/CSharp/String/RemovePart.cs .The other forms are quite inefficient generating multiple memory allocations by pressing the garbage collector and creating pauses in the application. People do without thinking later complain that they do not know why the application is slow, consuming a lot of memory.It is possible to still avoid the only allocation that is made using https://docs.microsoft.com/en-us/dotnet/api/system.span-1?view=netcore-3.0 . I didn't use it because it can only be used in certain situations and what the AP put in the question is not enough to know whether his situation is a candidate or not for his use. If it is Span can take the substring direct string original without any allocation, which is the best of the worlds.

If everything is properly formatted you could use this syntax, if I understood what you want would be something like this:x => String.Compare(x.CEPInicial, "03500-000") >= 0 && String.Compare(x.CEPFinal, "04000-000") <= 0 Another way that should work:x => x.CEPInicial.CompareTo("03500-000") >= 0 && x.CEPFinal.CompareTo("04000-000") <= 0 https://github.com/maniero/SOpt/blob/master/CSharp/Linq/IsRange.cs .These methods make the comparison and return:-1 if the value of the left is lower than that of the right0 if the values are equal1 if the value of the left is greater than that of the rightDocumentation https://docs.microsoft.com/en-us/dotnet/api/system.string.compareto?view=net-6.0&WT.mc_id=DOP-MVP-5002397#System_String_CompareTo_System_String_ and https://docs.microsoft.com/en-us/dotnet/api/system.string.compare?view=net-6.0&WT.mc_id=DOP-MVP-5002397#System_String_Compare_System_String_System_String_ .It only depends on actually having all digits placed correctly. If it's not like that, it becomes extremely complicated.When string has the first characters with greater magnitude than the following order can be established exactly as if done with number.However, if you are using this with Entity Framework, and the question does not say about it, but gives indications at one point, and gives indications that not in another (IEnumerable<CidadeAbrangencia>), you can generate a confusing SQL query or have problems. But it can be good because it depends on provider be very well done to understand these things.I do not guarantee that the result will be correct because even the question is unclear what would be the logic of this, but at least it would work and solve the problem reported.

Answering the question:Form 1 - using simple quotes:text: "Quero colocar um link aqui exemplo <a href='#'> Link </a>"; Form 2 - using exhaust:text: "Quero colocar um link aqui exemplo <a href=\"#\"> Link </a>"; Form 3 - inserting a variable with the URL:meulink = "#"; ... text: "Quero colocar um link aqui exemplo <a href=" + meulink + "> Link </a>"; Form 4 - Escape the whole text:text: `Quero colocar um link aqui exemplo <a href="#"> Link </a>`; Extra informationBased on your comments, you're probably confusing yourself by creating this array and object, as well as having trouble accessing on account of the first error. See:var novo_array = [ 0, 1, 234 ]; var novo_objeto = { idade: 23, nome: "José da Silva", funcao: "Desenvolvedor" }; var objeto_em_array = [ { texto: "Objeto dentro do índice 0 do array", texto2: "este também" } ]; Basically you are creating objects within an array. As your array has index 0, you access the items of the object so - according to the example above: objeto_em_array[0].texto I don't know why you two drenched or if it's necessary. If not, you can use only the object.I will provide a functional example of what you tried to do. Just look at the executable result and JavaScript. The rest is unnecessary for understanding and can be ignored because it only serves to see the execution (visual). Seevar resultados = [ { texto: "Clique aqui para abrir o poderoso <a href=\"https://www.google.com\">Google</a>!", texto2: "Another object" }, "Outro item do array", "Mais um item do array" ]; var popular = function(id){ alvo = document.getElementById(id); alvo.innerHTML = resultados[0].texto; };body { font-size: 12px; } #nav { width: 22em; text-align: center; } #formulario { float: left; width: 5em; margin: 0 2em 0 0; } #saida { float: left; width: 15em; } #cabecalho { background-color: #ffffaa; color: 333; padding: 0.5em; } #destino { padding: 0.5em; } .limpar { clear: both; }<div id="nav"> <div id="formulario"> <form> <input type="button" value="CLIQUE" onclick="javascript: popular('destino');" /> </form> </div> <div id="saida" > <div id="cabecalho">SAÍDA</div> <div id="destino"></div> </div> <div class="limpar"></div> </div>

You can use https://docs.python.org/3/library/functions.html#func-list to turn strings into lists. If you do list(string), the result is a list in which each element is a character of the string. Ex:print(list('teste')) This prints:['t', 'e', 's', 't', 'e']So just do this for each element of your list, and go adding these lists to your matrix (being that "matrix" is nothing more than a list of lists: a list in which each element is also a list):lista = ['teste', 'teste', 'teste', 'teste', 'teste'] matriz = [list(palavra) for palavra in lista] print(matriz) This prints:['t', 'e', 's', 't', 'e'], ['t', 'e', 's', 't', 'e'], ['t', 'e', 's', 't', 'e'], ['t', 'e', 's', 't', 'e'], 't', 'e'Note that I used the syntax https://docs.python.org/3/whatsnew/2.0.html#list-comprehensions , which is more succinct and https://pt.stackoverflow.com/q/192343/112052 . The above code is equivalent to:lista = ['teste', 'teste', 'teste', 'teste', 'teste'] matriz = [] for palavra in lista: matriz.append(list(palavra)) print(matriz)

Is there a way to remove the initial characters from the entire list without having to change their values one at a time?No, it doesn't exist. The very definition of the problem already indicates that. If you want to go through all the elements in the list to change your content, the only way is to go through all the elements.If the question was without using a tie I could say it depends. It is virtually impossible to do without a loop, one way or another. The only way is to manually make each element, which is a maluquice.Then you should be saying, but the other answer showed you can do. But it really doesn't. It gives to hide the loop, as you can do in any function, as it gives to do whenever you create a https://pt.stackoverflow.com/q/360556/101 . The question is that .NET already has a prompt abstraction called https://pt.stackoverflow.com/q/182176/101 .What LINQ does is go through enumerable objects, as is the case with the list. How does he cross a list? Through a tie. There's no magic, except she's in a method.So it's always better to use LINQ? No. It depends on what you want to do. If you want to manipulate the data more complexly, LINQ may not be a good one. If you need performance, LINQ does not meet you well, it has a considerably higher cost when this is important. Take the test with both.But is this the cost? No, it creates a new list, makes new allocation and is inefficient and can provoke unwanted pauses in the application more often.Of course, all this depends on a number of factors, but if you use indiscriminately without knowing how each abstraction works will get involved in problems, so you need to understand everything and make the most appropriate decisions. It can't be the nicest choice.Is he much shorter and obvious? No, just a little, see the difference:for (int i = 0; i < lista.Count; i++) if (s.Length > 3) lista[i] = lista[i].Substring(3); lista = lista.Select(s => s.Length > 3 ? s.Substring(3) : s).ToList(); https://github.com/maniero/SOpt/blob/master/CSharp/Linq/Substring.cs .

You have, to create a function that does this, that is to create an abstraction to meet the requirement of being a single command. But as every command in the language does not mean that it will be a single instruction to be executed. The naive way to do this would be something like this:def mulipleReplace(text): for char in ".!?,": text = text.replace(char, "") return text But this is extremely inefficient because string is unchangeable, so each of these operations will generate a new string, allocating memory that is something expensive, even because then you will have to copy everything, you will have to release that arrives to be more expensive yet, and potentially can clog memory. The most idiomatic way to solve this would be:def mulipleReplace(text): return "".join([char if char in ".!?," else "" for char in text) See https://ideone.com/TGAC9J . And https://repl.it/join/zdltkrhf-maniero . Also https://github.com/maniero/SOpt/blob/master/Python/String/RemovePonctuation.py .This form creates a list of characters that interests and then turns the list into string.You can still do with RegEx, which I don't like until because it's usually inefficient (I don't guarantee in this case because I test little in Python, if you want to test all options before you do, and you have several other ways to do the same, but I have confidence that the previous one is very fast and probably the fastest), something like this:texto = re.sub(".!?,", texto, "") Don't forget you have to import the module re.Moral of the story: programming is not to infiltrate commands that we do not understand what we do, it is to understand the whole process that occurs on the computer, in the technology that is using and know that to solve problems, the real profession we exercise is necessary to have methodology and technique. It has several ways to do, but most need consciousness, can not be just copy and paste, and may not exist ready, or the ready is not ideal.

Using xml I found some answers here: https://stackoverflow.com/questions/6061470/if-then-else-using-xml Or using xslt this way:<xsl:if test="1 == 2"> <property name="SHAZAM" value="Esse é o conteúdo ${env.SHAZAM}"> </xsl:if>

First, the data you are using is descriptive, that is, it is a text and should not convert to number in any hypothesis, it is not a number, only coincidentally the text only has numeric digits.And if it were to make conversion it is not so that it is done on VB.NET, that is something that old VB and should no longer be used. The correct way has already been answered in several questions here (although all in C# is the same thing), https://pt.stackoverflow.com/q/213057/101 .Then the correct one is:TxtCgc.Text = numcgc.Substring(0, 3) + "." + numcgc.Substring(3, 3) + "." + numcgc.Substring(6, 3) + "-" + numcgc.Substring(9, 2) https://github.com/maniero/SOpt/blob/master/VB.NET/String/FormatString.vb .In fact you need to validate this data more, a lot can come wrong.

The strings are not "equal" - if one is with all non-ASCII characters encoded with "%XX", it has to be decoded before. The default library has the function urllib.parse.unquote that can transform coded characters in this way into text characters. It has one more important thing to note there: you can note that as you have two bytes to represent a single accented character (and the first having \xC3 code is another tip), in addition to the escape in url-quote, this original string was encoded in utf-8. Utf-8 is the default encoding that the unquote of Python therefore considers only calling this function directly solves:In[202]: import urllib.parse In [203]: name1 = 'G%C3%A9rard Depardieu' In [204]: print(urllib.parse.unquote(name1)) Gérard Depardieu If, in your data, you find encoded characters as a single byte, this may mean that the original string encoding was in latin1. In this case it is only encoding in the "encoding" parameter of the function unquote:In [206]: urllib.parse.unquote("G%e9rard", encoding="latin1") Out[206]: 'Gérard' how to do:The best thing you do is to de-screw these strings as soon as you read them into your program. In the question you do not say if they are in a file, if they arrive in a Web request, etc... but if they were like this inside a file - you could do so:from urllib.parse import unquote with open("meu_arquivo.txt") as file: text = unquote(file.read()) lines = text.split("\n")

The difference is that one you don't see and the other you see, nothing more. The difference is the method println().nothing happensWrong wishes.an instance time has been createdIt contradicts the premise.The first creates the new instance and nothing else can be done with that. It cost to create, occupied memory and will stay there until the object is collected. The second code passes this object through a reference to the method println() do what he knows how to do, so potentially he will have a https://pt.stackoverflow.com/q/135572/101 guaranteed a little higher, but in practice we know that it does not matter in a simple example, the object will only be available for a moment in its creation and execution of the method.In fact the problem itself has nothing to do with the fact that the object is immutable, that is circumstantial, any object that was created would occur the same.Perhaps it lacks understanding of what is a https://pt.stackoverflow.com/q/181332/101 , it is simpler than people imagine.

Unlike JavaScript that has weak typing, TypeScript does not allow automatic coercion of types that can bring problems in some circumstances, so the only way to deal with values of different types is by converting one of them to compatibilize, as you want it to be text should create a String or convert using the method https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Object/toString .You have another question. The fact of the language being static typing, for the good in my view, a variable cannot change type, so the variable that was number cannot receive a text, so it should create another variable with the type String to receive the results.I'll put it in JS because the syntax is identical in both languages, the semantic is that it changes, the beauty of the TS is precisely this, not letting a possible error occur, but nothing else:function teste() { var today = new Date(); var dd = today.getDate(); var mm = today.getMonth() + 1; var yyyy = today.getFullYear(); var d = ""; var m = ""; if (dd < 10) d = '0' + String(dd); if (mm < 10) m = '0' + String(mm); console.log(d); console.log(m); } teste();Or if you prefer:function teste() { var today = new Date(); var dd = today.getDate(); var mm = today.getMonth() + 1; var yyyy = today.getFullYear(); var d = ""; var m = ""; if (dd < 10) d = '0' + dd.toString(); if (mm < 10) m = '0' + mm.toString(); console.log(d); console.log(m); } teste();Note that you can turn the number into text in both ways as I put it, they are interchangeable, you can choose which one finds best.If you prefer you can do as Valdeir spoke and works well in both languages, it is a way even more recommended for generic solution because you will have problems with the months 10, 11 and 12:function teste() { var today = new Date(); var dd = today.getDate(); var mm = today.getMonth() + 1; var yyyy = today.getFullYear(); var d = dd.toString().padStart(2, '0'); var m = mm.toString().padStart(2, '0'); console.log(d); console.log(m); } teste(); https://github.com/maniero/SOpt/blob/master/TypeScript/String/Pad.ts .

I think you have a better way, but I couldn't think of that right. But I think what I've done is good.<?php $string = "0/ 0/0 0 maria online 0/ 0/0 0 joão off"; $count = 0; $ar = explode(" ", $string); foreach ($ar as $ar) { if($ar != ""){ if ($count <= 4) { $dbArray[0][] = $ar; }else{ $dbArray[1][] = $ar; } $count++; } } /* versão sem loopping ou condicionais $dbArray = [ 0 => [ 0 => $ar[0].$ar[1], 1 => $ar[3], 2 => $ar[5], 3 => $ar[6] ], 1 => [ 0 => $ar[7].$ar[8], 1 => $ar[10], 2 => $ar[12], 3 => $ar[13] ] ]; */ var_dump($dbArray);

Use the argument drop = TRUE. The code should look like this:umParticipante[5, 1, drop = TRUE]Explanation:When you pass the argument drop = TRUE, the R turns the result into a vector and will look the way you expect.If you do not pass the argument drop, or pass drop = FALSE, the result is transformed into a new tibble with only one row and column.

How it comes to a JSON recommend using the library https://www.newtonsoft.com/json to get the data you want.Just make a parsing using the class JArray and one foreach get the key values tag so you can fill your list of strings, for example: using System; using System.Collections.Generic; using Newtonsoft.Json.Linq; public class Program { public static void Main() { var json = "[{"tipo":"simnao","pergunta":"rwerw#erwerewr ?","tag":"#acimadopeso","resposta":"","$$hashkey":"object:410"},{"pergunta":"werwerwerwer ?","tag":"#diabetes","resposta":"","$$hashkey":"object:412"},{"pergunta":"werwerwer ?","tag":"#idoso","resposta":"","$$hashkey":"object:414"}]"; JArray array = JArray.Parse(json); var tags = new List<string>(); foreach (var a in array) tags.Add(a["tag"].ToString()); } } Output tags.ForEach(x => Console.WriteLine(x));#acimadopeso#diabetes#idoso See working on https://dotnetfiddle.net/LzsHMg .

Your code is correct, the only thing that's wrong is to search for the code. The correct would be to do the same way as you did to search for by the product name.Remembering how you are converting the code entry to a number codigo = int(input("Código do produto: ")), if the values in the list of codes are strings, e.g. codigos = ["10", "20", "30"], the comparison will always be false.10 == 10 > True "10" == 10 > False #tipos diferentes "10" == "10" > True def procurando(escolha, codigos, produtos, precos): print(codigos) verdade = False if escolha == 1: codigo = int(input("Código do produto: ")) for i, v in enumerate(codigos): print("entrou no for") print(codigo) print(v) if codigo == v: print("entrou no if?") verdade = True print("Produto: {} Preço: {}".format(produtos[i], precos[i])) break; elif escolha == 2: nome = input("Nome do produto: ") for i, v in enumerate(produtos): print(produtos[i]) if v == nome: print("Foi encontrado 1 resultado.") print("Produto: {} Preço: {}".format(produtos[i], precos[i])) verdade = True break; print(verdade) return verdade

Beyond this code not be idiom C# (it appears that it was written in another language), it does many things without need, including memory allocation.The main change is not to allocate a new object which is something that can create a problem of change, I only made comparisons because the problem only asks for it. And comparing one by one is the best way. Although it is not visible these methods that are using are composed of loops, they sweep the entire data every time, it is very bad.Another change is to get out so soon know that it is not palendrome, and that should occur a lot, it is easy not to be. When you already know that it is not because you continue the algorithm.Lastly, I only check until half, because if I continue the result it is already known. What would I differ from analyzing the first with the last and then the last with the first? Same thing.I haven't improved validation because I don't know the requirements.using static System.Console; public class Program { public static void Main() { WriteLine(checkPalindrome("ana")); WriteLine(checkPalindrome("abba")); WriteLine(checkPalindrome("oki")); } static bool checkPalindrome(string inputString) { if(inputString.Length >= 1 && inputString.Length <= 100_000) { for (var i = 0; i < inputString.Length / 2; i++) if (char.ToLower(inputString[i]) != char.ToLower(inputString[inputString.Length - i - 1])) return false; return true; } return false; } } See https://ideone.com/ySUYG5 . And https://dotnetfiddle.net/d9mrx2 . Also https://github.com/maniero/SOpt/blob/master/CSharp/Algorithm/Palindrome.cs .

You are confusing letter with text (face with string).In C a letter or a cartere is defined by the type char.A string or text is defined as an array of characters and will normally be written as char[] or char*.To modify a cartere simply change directly as if it were an entire or other basic type:char letra = 'a'; letra = 'z'; Now if you have a text you cannot modify directly because the text is actually a set of letters (array) and should make the change based on the function http://www.cplusplus.com/reference/cstring/strcpy/ :char texto[30] = "ola"; strcpy(texto, "mundo"); In your code you have only one letter but are trying to change with strcpy that is for texts, so it is not correct. In addition to concatenate means adding a letter to a text that also does not represent what you are doing.The solution goes by removing strcpy that is not correct and put a normal assignment of a char, as p->simbolo = E;.Now answering the question you have in the title and that is not what you want to do:How to concatenate a char in a string?For this can:Check where the last cartere ends through strlenPlace the new cartere in the position given by strlenReset the terminator after the new letterImplementation:void concatenar_letra(char texto[], char letra){ size_t tamanho = strlen(texto); texto[tamanho] = letra; texto[tamanho + 1] = '\0'; //recolocar terminador } https://ideone.com/kwCuOu Keep in mind that this function assumes that there is space allocated in the string for the new cartere, otherwise you incur in indefinite behavior, or have to add more things to validate.To concatenate two texts already has a function of C libraries for this, the http://www.cplusplus.com/reference/cstring/strcat/ .