Well, I found a way to do, I don't know if it's the most correct, but this function is returning me the link from the generated file.DocumentControler. ♪//passo o título do arquivo que tenho salvado no banco de dados @GetMapping("/download/title={title}") public File download(@PathVariable("title") String title) { Document document = service.findByTitle(title); //busco o documento pelo título File file = new File(title + ".txt"); //adiciono o título como nome do arquivo try (Writer writer = new BufferedWriter(new FileWriter(file))) { String contents = document.getDescription(); writer.write(contents); //adiciono o conteúdo do documento ao arquivo return file; //retorno a url onde ele foi gerado. } catch (IOException e) { e.printStackTrace(); } return null; } So just access the url and download the file.

The archive pom. xml, add the following configuration:<build> <resources> <resource> <filtering>true</filtering> <directory>src/main/resources</directory> <includes> <include>sistema.properties</include> </includes> </resource> </resources> </build> Create a property file in the src/main/resources directory For example: system. properties Every time you perform the task of Maven, the file will be updated.You can access the property file values anywhere in the system, including a JSP.

I used the tag th:replace and it worked.

In the model class add annotation _package org.springframework. data.redis.core.index. Indexed;@Data @RedisHash("customer") public class Customer { @Id private String id; @NotNull @Indexed private String firstName; ...

In the link of your JSP, you should indicate the context of your application, as the example below:<a href="${pageContext.request.contextPath}/hello/controller/"> Hello </a> The expression will concatenate the context of your application to the link, directing to the correct address.UPDATE: Referring to the configuration of your application being directly in the localhost:8080 URL, you must deploy directly to the server's ROOT context. For this you can change the context of your application in the file server.xml, in the tag context you will see the context of your application, this way it is just to change to /.In Eclipse: Aba Server > Modules > Change the application context to /Important: If you change the context of your application to directly use the root, the ${pageContext.request.contextPath} will no longer be necessary as indicated above.UPDATE: How after including ${pageContext.request.contextPath} you managed to get to your @Controller, if you are still presenting 404 is due to incorrect targeting of your page view.jspTry the form below:return new ModelAndView("hello/view", // Trocando de /hello/view para hello/view ...

As the system in question is using Spring Security, then I found the solution in this stackoverflow resolution https://stackoverflow.com/questions/28647136/how-to-disable-x-frame-options-response-header-in-spring-security With this just put in the settings of sprinf security:http .headers() .frameOptions() .sameOrigin() .and() Before the other settings I had already added, it solved the issue of FRAME to DENY.

Try changing the order of the Controller parameters@RequestMapping("/lista-receitas") @ResponseBody public String recebeLista(@RequestParam("nome") String nome, @RequestBody List<Receita> receitas){ System.out.println("Receita: "+ nome); for(Receita r: receitas){ System.out.println("ID: "+r.getId() +" Nome: "+ r.getNome()); } return "Sucesso"; }

Yes, just use @RequestBody and create a POJO class that contains a String id attribute. Note that you will not be able to pass the href of the link, so you will have to create a request by forwarding json via Javascript.For example:@GetMapping("/pessoa/") public ModelAndView editaPessoa(@RequestBody PessoaInterface pessoa) { ..... } PersonInterface. ♪public class PessoaInterface { String id; public String getId() { return id; } public void setId(String id) { this.id = id; } } Note that in PersonInterface. java you can add a List and pass numerous IDs in a single request.Ideal solutionYou are using the GET method to make an issue. One of the principles of REST is to respect HTTP codes and use the correct verbs, that is, use GET only in a case where you need to access something. The ideal is for you to use PUT or PATCH for the edition (I can't state which for sure because I don't know your scenario). Note that it is not only a matter of respecting the patterns, there is a long thread on forwarding body in a GET request ( https://stackoverflow.com/questions/978061/http-get-with-request-body ) and some servers even refuse by default GETs requests with body. Speaking of REST, that is certainly not accepted.What if I wanted to get an element without having to pass the ID?Supposing that your problem is not a person issue and yes getting a person passing through the ID, in these cases we continue to pass through via path param but GUIDs are used instead of IDs.

Friend, I believe that the error referred to is that you have not placed @ModelAttribute the name of the object you refer to and that is in the view. Test this:@GetMapping("/cadastro") public ModelAndView preSalvar(@ModelAttribute("medico") Medico medico, @ModelAttribute("especialidade") Especialidade especialidade){ return new ModelAndView("home","conteudo","medico/add"); }

Well, after the help of a friend of the GUJ forum and a little research I came to the conclusion that for popular my list would have the possibility of doing for two ways, AJAX or removing my modal from my form and creating another form invoking an action in my controller and thus populating an List.I chose to do by submitting a separate form, because I don't have much intimacy with AJAX calls yet. Below is the implementation:×Close Register New Passenger <div class="aling-form col-sm-12 nest text" style="padding-top:25px"> &lt;div class="box01"&gt; &lt;select id="familyBond" class="form-control" name="familyBond"&gt; &lt;option value="null" label="-- Vinculo do Passageiro --" /&gt; &lt;c:forEach items="${listOfBondNames}" var="bond"&gt; &lt;option value=""&gt;${bond.value}&lt;/option&gt; &lt;/c:forEach&gt; &lt;/select&gt; &lt;/div&gt; &lt;div class="box02"&gt; &lt;input id="passenger-name" placeholder="Nome do Passageiro" name="firstName" type="text" class="form-control"/&gt; &lt;/div&gt; &lt;div class="box01"&gt; &lt;input id="passenger-lastName" placeholder="Sobrenome do Passageiro" type="text" name="lastName" class="form-control"/&gt; &lt;/div&gt; &lt;div class="box02"&gt; &lt;div class="input-group "&gt; &lt;span class="input-group-addon btn-success"&gt;&lt;i class="fa fontawesome-envelope-alt"&gt;&lt;/i&gt;&lt;/span&gt; &lt;input id="passenger-email" placeholder="E-mail" type="text" name="email" class="form-control"/&gt; &lt;/div&gt; &lt;/div&gt; &lt;div class="box01"&gt; &lt;div class="input-group "&gt; &lt;span class="input-group-addon btn-success"&gt;&lt;i class="fa fa-phone-square"&gt;&lt;/i&gt;&lt;/span&gt; &lt;input id="passenger-phone" placeholder="Telefone Principal" type="text" name="mainTel" class="form-control"/&gt; &lt;/div&gt; &lt;/div&gt; &lt;div class="box02"&gt; &lt;div class="input-group "&gt; &lt;span class="input-group-addon btn-success"&gt;&lt;i class="fa fa-calendar"&gt;&lt;/i&gt;&lt;/span&gt; &lt;input id="passenger-birth" placeholder="Data de Nascimento" type="text" name="birthDate" class="form-control"/&gt; &lt;/div&gt; &lt;/div&gt; &lt;div class="box01"&gt; &lt;input id="passenger-rg" placeholder="RG" type="text" name="documentPassenger.rg" class="form-control" style="margin:0px;"/&gt; &lt;/div&gt; &lt;div class="box02"&gt; &lt;input id="passenger-cpf" placeholder="CPF" type="text" name="documentPassenger.cpf" class="form-control"/&gt; &lt;/div&gt; &lt;input type="hidden" name="${_csrf.parameterName}" value="${_csrf.token}" /&gt; &lt;/div&gt; &lt;/div&gt; &lt;div class="modal-footer clear" style="margin:0px;"&gt; &lt;button type="button" class="btn btn-danger" data-dismiss="modal"&gt;Cancelar&lt;/button&gt; &lt;button type="submit" class="btn btn-primary"&gt;Cadastrar&lt;/button&gt; &lt;/div&gt; &lt;/form&gt; &lt;/div&gt; &lt;/div&gt; &lt;/div&gt; Soon he calls the action:private List<Passenger> passengerList = new ArrayList<Passenger>(); @RequestMapping(value="/addPassenger", method=RequestMethod.POST) public ModelAndView addPassenger(Passenger passenger, Model model){ passengerList.add(passenger); ModelAndView mv = new ModelAndView("service/newService"); mv.addObject("passengerList", passengerList); mv.addObject("customer", new Customer()); initializeComponents(model); return mv; } With this approach I have my passengerList populated for when submitting my main form I will be able to tie the list in bean.

Juan, good morning!This passage says your problem: 1: ArgumentException: O valor "SGB.Services.Spec.DataTransferObjects.DTOComposicaoBeneficioBeneficiario" não é do tipo "SGB.Domain.Entities.ComposicaoBeneficioBeneficiario" e não pode ser usado nesta coleção genérica. How C# is a strongly typed language (Strogly Typed), the compiler does not automatically convert to you. The type he is expecting is "SGB.Domain.Entities.ComposicaoBeneficioBeneficiario", make sure the class being used is not exchanged.

Sorry, buddy, I don't know if I can understand what you need and what your difficulty, but let's go.I noticed some strange things in your method to searchNumeroCaderno and so I would like to leave some questions.If the intention is only to search by notebook number, why is passing as parameter CadernosCadastrados, statusPendente, statusFinalized and id? Also none of these parameters are being used in the method body.From what I understand, when conducting a survey, the system must return a form with the notebook data and the information if it is new, pending, finalized or non-existent. If the return of this method is a page form why daoCadernosCadastrados.buscarNumeroCaderno(numeroCaderno) returns a list of notebooks? Can have in the database more than one notebook with the same number? If this is possible, where is the treatment of this possible return? Because it is not usual to display more than one notebook in one form. If this is not possible, it is good to review the implementation of CadernosCadastrados.buscarNumeroCaderno(numeroCaderno) and leave the return consistent with the situation.After you observe these issues and leave the code clearer it will be possible to assist you more accurately, but to do what you need to believe that the code below resolves, it is not the best way but is already one step further from the original version:@GetMapping("numeroCaderno") public String buscarPorNumeroCaderno(Model model, String numeroCaderno) { Caderno caderno = daoCadernosCadastrados.buscarNumeroCaderno(numeroCaderno); if (caderno != null) { model.addAttribute("mensagem", ""); model.addAttribute("caderno", caderno); if (enumStatus.PENDENTE.equals(caderno.status)) { return "public/caderno_pendente"; } if (enumStatus.FINALIZADO.equals(caderno.status)) { return "public/caderno_finalizado"; } return "public/caderno_novo"; } return "public/sem_resultados"; }

I've lost a lot of time trying to solve this problem. I hope that's what I've been through.Next, you have two options:1 - Tell Spring to ignore the ROLE_ prefix.@Override public void configure(WebSecurity web) throws Exception { web.expressionHandler(new DefaultWebSecurityExpressionHandler() { @Override protected SecurityExpressionOperations createSecurityExpressionRoot(Authentication authentication, FilterInvocation fi) { WebSecurityExpressionRoot root = (WebSecurityExpressionRoot) super.createSecurityExpressionRoot(authentication, fi); root.setDefaultRolePrefix(""); //remove the prefix ROLE_ return root; } }); } Credits: https://stackoverflow.com/questions/38134121/how-do-i-remove-the-role-prefix-from-spring-security-with-javaconfig 2° - Add ROLE_ as prefix in your permissions.public static final String ROLE_PREFIX = "ROLE_"; public String getRole() { return ROLE_PREFIX + this.nomePermissao; }

Try to specify the type of request: Post, Get, etc. In your case I believe it is a Post, so the method would look like this: @Controller @RequestMapping("/funcionarios") public class ManterFuncionarioController { @RequestMapping(method = RequestMethod.POST, path = "/criar") public String criarFuncionario(Model model, Funcionario funcionario, Usuario usuario, BindingResult result){ ///METODO/// } } In the above example to save you will have to access http://localhost:8080/funcionarios/criar and specify your request as Post.

In your controller the url is "/category", but the request in fetch is for "/FlowerLiu/note", change the url so that they are equal, the request must be accessing another existing resource.

Every time you will include an item in the order you call the inclusion service to update the order? This way your application will drop a lot in performance. I suggest you control your list of items in the front end, basically adds and deletes items in the list and then a check out button or finalize order, so yes you create your order with the items. Example: @PostMapping public ResponseEntity<Void> insert(@Valid @RequestBody Pedido obj) { obj = pedidoService.insert(obj); URI uri = ServletUriComponentsBuilder.fromCurrentRequest() .path("/{id}").buildAndExpand(obj.getId()).toUri(); return ResponseEntity.created(uri).build(); } @Transactional public Pedido insert(Pedido obj) { obj.setId(null); obj.setInstante(new Date()); obj.setCliente(clienteService.find(obj.getCliente().getId())); obj.getPagamento().setEstado(EstadoPagamento.PENDENTE); obj.getPagamento().setPedido(obj); if (obj.getPagamento() instanceof PagamentoComBoleto) { PagamentoComBoleto pagto = (PagamentoComBoleto) obj.getPagamento(); boletoService.preencherPagamentoComBoleto(pagto, obj.getInstante()); } obj = pedidoRepository.save(obj); pagamentoRepository.save(obj.getPagamento()); for (ItemPedido ip : obj.getItens()) { ip.setDesconto(0.0); ip.setProduto(produtoService.find(ip.getProduto().getId())); ip.setPreco(ip.getProduto().getPreco()); ip.setPedido(obj); } itemPedidoRepository.saveAll(obj.getItens()); return obj; } I hope that helped you.

Hi.The methods you are using suggest that you have a Map (method put) and an ArrayList (method findAll), hence your map and your myArrayList.The right thing to do is to have a POJO that represents the object to be returned by your API, and populate it with user data and posting.For example: public class PostagemDTO { private Usuario usuario; private List<Postagem> postagens; // getters e setters } So your API will return the desired result.I hope you help!

it is falling into this exception because you are incorrectly calling your endpoint, when you call the path /clients/list actually you are passing the string "list" pro your view method, which causes your exception, the right would be customers/15 for example, being 15 your client's id, or just customers to call the list methodediting here the answer because I realized that you have several errings seeing your git 1 Your methods of your controllers, realize that you are using the ModelAndView method by passing the view name, model name, and then the model object, your model is called a client, and when you pass it by passing customers in the plural in some calls, you need to be equal because otherwise it doesn't identify. 2° your view method you are getting a model but put the id name, I think you got confused here, when I see you should exchange this Customer for long id 3° still in your view method, you're passing the customer with nothing, that la on the front will give an exception for null, changing his method he stayed like this for me:@GetMapping("{id}") public ModelAndView view(@PathVariable("id") long id) { Cliente cliente = new Cliente(id, "Lucas", "123456"); //essa parte aqui você deve trocar pelo seu select return new ModelAndView("view", "cliente", cliente); } 4° in your html you put in the view that is making error in line 10 th:if="{globalMessage}", there is a scarlet here and so it was making a mistake to parsear, the right would be th:if="${globalMessage}"

If you simply want to return a string using as text/plain, please place @ResponseBody annotation in your method:@RequestMapping("/olaMundoSpring") @ResponseBody public String execute() { System.out.println("Executando a lógica com Spring MVC"); return "ok"; } As far as I could tell the Spring MVC may be using jsp with view handler, as it does not find an ok.jsp or something of the same kind responds with 404.

After mta research, although ngm aqi give me the answer, I managed to find, and I will answer aqi if someone else has this problem, the class stayed like this:@Component @ConfigurationProperties(prefix = "spring.datasource") //aqi no prefix eh pra colocar qual o caminho q ta as propriedades public class ConnectionFactory { private String username; private String password; private String url; private String driver_class_name; //getters e setters } If vc create your attributes with the same attributes name q vc placed the value la in the file .properties The Spring msmo already connects them under the cloths, ae is just use the getters to pick up the values. And if you want to use in another class just create a property there like this:@Autowired private ConnectionFactory connection; and use this property to catch the values.That's it, vlw flw!