Add to the Test array Question, and remove it from Question field Test[XmlElement ( ElementName = "Question" )] public Question[ ] Questions; You have a weird logic to me. The code does not refer to the test, but the question test, and the logic is correct in the xml file.

Your attempt with a scanner is incomplete, so try:protected void doPost(HttpServletRequest request, HttpServletResponse resp) throws ServletException, IOException { StringBuilder stringBuilder = new StringBuilder(1000); Scanner scanner = new Scanner(request.getInputStream()); while (scanner.hasNextLine()) { stringBuilder.append(scanner.nextLine()); } String body = stringBuilder.toString(); System.out.println("Scanner: " + body); }

First, WriteableBitmap It doesn't show, so it's been replaced. URISecond ObservableCollection<Т> should be transformed into List<T>The code will be next. var file = await savePicker.PickSaveFileAsync(); var ser = JsonConvert.SerializeObject(this.ImageList.ToList()); await FileIO.WriteTextAsync(file, ser);

[a: 1, b: 2, 3, d: 4]That's not possible ) That's it.JSON.stringify({a: 1, b: 2, c: 3, d: 4})

I found a solution by turning ajax request into an ordinary post-request. Turns out, the problem is, in my essence, Entity was not a set-Id method.<?php namespace FarmBundle\Entity; class Garden { /** * @return $this */ public function setId($id) { $this-&gt;id = $id; return $this; } }

serializeArray() apply not to each counter separately but to all forms

In order to fully answer the question, it is desirable to know the API server (as expected by the facility) and to have an idea of sending the facility. But I'll try to provide a detailed response based on possible options. Option 1.The Server expects a URL in one of the following formats.Divided commas. Example:http://ex.com/doIt?array=el1,el2,el3Repeat name of parameter. Example:http://ex.com/doIt?array=el1&array=el2&array=el3These options are suitable for the transfer of a range of primitive types. Option 2.Server expects JSON to have a mass or object encoded with help. http://docs.oracle.com/javase/8/docs/api/java/net/URLEncoder.html or something similar. Example:http://ex.com/doIt?array=%5B%22el1%22%2C%22el2%22%2C%22el3%22%5DIt fits for complex types.Option 3.Server's expecting an object in binary form encoded in the row. https://ru.wikipedia.org/wiki/Base64 ♪ Example:http://ex.com/doIt?array=YmFzZTY0U3RyaW5nFor coding, there are standard applications https://docs.oracle.com/javase/8/docs/api/java/util/Base64.html and http://developer.android.com/reference/android/util/Base64.html and side, for example https://commons.apache.org/proper/commons-codec/apidocs/org/apache/commons/codec/binary/Base64.html ♪ Not a theme.The following does not apply to requests for non-replaceable data on the server (filtration, etc.)The transfer of the facility to keep it on the server with GET request is a bad HTTP design (or REST as anyone likes) API server. For several reasons:GET method by definition http://lib.ru/WEBMASTER/rfc2068/section-9.html#p1 should be https://ru.wikipedia.org/wiki/%D0%98%D0%B4%D0%B5%D0%BC%D0%BF%D0%BE%D1%82%D0%B5%D0%BD%D1%82%D0%BD%D0%BE%D1%81%D1%82%D1%8C ♪ i.e. by-products from N &gt; 0 identical requests as from a single request.There are restrictions on the length of URL browsers, proxy and web servers.GET requests can be encrypted.A search crower, somehow getting this link, can make a lot of duplicates in your OBD.

Because the controller has a reference to parental control, and that list of references to children has closed.You can write your screwdriver with only the properties you want to preserve.public class ControlWrapper { private Control fControl; public ControlWrapper(Control aControl) { fControl = aControl; } public int Width { get { return fControl.Width; } } ... } JavaScriptSerializer serializer = new JavaScriptSerializer(); string json = serializer.Serialize(new ControlWrapper(label1));

Your problem is that File.OpenWrite doesn't erase the old file, but writes it up. If the number of information recorded is reduced, the file remains trash.Use the call. File.Open(namesDB, FileMode.Create, FileAccess.Write)♪

They say no matter what you're in. ArrayList-e, the main thing is that the objects are scattered, that is, your class should be implemented from the interface. SerializableSerialization:try { FileOutputStream fileOut = new FileOutputStream(sdDir + serFile); ObjectOutputStream out = new ObjectOutputStream(fileOut); out.writeObject(arrayList); out.close(); fileOut.close(); } catch (FileNotFoundException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } Desertion:try { FileInputStream fileIn = new FileInputStream(sdDir + serFile); ObjectInputStream in = new ObjectInputStream(fileIn); arrayList = (ArrayList<ItemList>) in.readObject(); Log.i("palval", "dir.exists()"); in.close(); fileIn.close(); } catch (ClassNotFoundException e) { e.printStackTrace(); } catch (FileNotFoundException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); }

XmlSerializer not supporting mixed contents.You can:Use the castle screaming. https://msdn.microsoft.com/ru-ru/library/system.xml.serialization.ixmlserializable(v=vs.110).aspx )For class ENR31Title Use XElement♪In both cases, the motorized code will have to be modified.

He didn't go deep. nestablebut noted the following:The Library will only be perceived as lists <ol> (if not otherwise specified when a copy is created). Since your top level is <ul>♪ nestable it is not taken into account in the event of a series; I changed accordingly. <ul class="dd-list"></ul> ♪ <ol class="dd-list"></ol> and $('#nestable ul').append(buildItem(item)); ♪ $('#nestable > ol').append(buildItem(item)); and the serialization has become correct;In the library, an indication of the class for the root element is required to address the elements within the list <div id="nestable">♪ Since it was not specified, the retreading of elements was not working.Working option: http://jsfiddle.net/53WSc/13/

Try this:internal class Program { private static void Main(string[] args) { var ch = new MyChild(); ch.Id = "123"; ch.Name = "Stefani"; var parameter = new InnerParameter(); parameter.Value = "MyText"; ch.Child.Add(parameter); string result = XmlHelper.ObjectToXmlString(ch); } public static class XmlHelper { public static string ObjectToXmlString(object obj) { var xmlSerializer = new XmlSerializer(obj.GetType()); using (var textWriter = new StringWriter()) { xmlSerializer.Serialize(textWriter, obj); return textWriter.ToString(); } } } } So the question was edited - this is a new decision to correct the error that your code gives:[Serializable, XmlInclude(typeof(MyChild))] [XmlRoot("Main")] Just add XmlInclude.

Serialization is the transformation of the object or tree of the objects into a format so that they can be rebuilt from that format. Used, for example, to maintain the programme (i.e. some of its facilities) between launches. Or for the transmission of data between different copies of the programme (or different programmes), e.g. the network.The main idea is that a series format is a set of byte or line, which can be easily stored on a disk or transferred to another process or, for example, online, unlike the facility itself. Thus, the task of maintaining the object/group of objects is simply to maintain the set of byte or line.JSON is one of the popular formats for the showing, he's textual, light and easily read by man.Example: If you have a classclass Test { int length; String name; public Test(int length, String name) { this.length = length; this.name = name; } } The object of this class in a seriesed form can be seen{ "length": 25, "name": "Имя" } The series itself (and deserization) can be performed manually or used by appropriate libraries/freimvors.There are also binary formats of the show.

This can be done as follows.We'll use the ready class. XmlAttributeOverrides but we'll do a couple of extension techniques to add strict typology:public static class XmlAttributeOverridesHelpers { public static void Add<T>(this XmlAttributeOverrides overrides, Expression<Func<T, dynamic>> propertySelector, XmlAttributes attributes) { overrides.Add(typeof(T), propertySelector.BuildString(), attributes); } public static string BuildString(this Expression propertySelector) { switch (propertySelector.NodeType) { case ExpressionType.Lambda: LambdaExpression lambdaExpression = (LambdaExpression)propertySelector; return BuildString(lambdaExpression.Body); case ExpressionType.Convert: case ExpressionType.Quote: UnaryExpression unaryExpression = (UnaryExpression)propertySelector; return BuildString(unaryExpression.Operand); case ExpressionType.MemberAccess: MemberExpression memberExpression = (MemberExpression)propertySelector; MemberInfo propertyInfo = memberExpression.Member; if (memberExpression.Expression is ParameterExpression) { return propertyInfo.Name; } else { // we've got a nested property (e.g. MyType.SomeProperty.SomeNestedProperty) return BuildString(memberExpression.Expression) + "." + propertyInfo.Name; } default: // drop out and throw break; } throw new InvalidOperationException("Expression must be a member expression: " + propertySelector.ToString()); } } May be applied as follows:var overrides = new XmlAttributeOverrides(); var ignore = new XmlAttributes { XmlIgnore = true }; overrides.Add<MyClass>(m => m.Id, ignore); overrides.Add<MyClass>(m => m.DateChanged, ignore); Type t = typeof(List<MyClass>); XmlSerializer serial = new XmlSerializer(t, overrides); The solution was found https://stackoverflow.com/a/9413711/5610621

You need to. JsonExtensionDataAttribute♪ But there's a limitation - I understand it can only be a kind of implementation. IDictionary<string, JToken>♪

as far as Tag and some object field can be scattered if it is not known in advance what specific implementation (TableTag, PictTag, TextTag) it will be initiatedImpossible, it's a restriction on XML-serialization at NET. You must Right. When compiling, which types will be deserized.In your case, it might be that code:[XmlInclude(typeof(TableTag)), XmlInclude(typeof(PictTag)), XmlInclude(typeof(TextTag))] abstract class Tag { [XmlIgnore] abstract object Value { get; } } class TableTag : Tag { public DataTable TableValue { get; set; } [XmlIgnore] public override object Value { get { return TableValue; } } }

Classes for specific json can be seduced directly in the studio - Edit / Paste Special / Paste JSON as Classes:public class RecyclerData { public string url { get; set; } public ChildData[] childitems { get; set; } } public class ChildData { public string Data { get; set; } } List<RecyclerData> It's in your JSON.var list = new List<RecyclerData>() { new RecyclerData { url = "www.ya.ru", childitems = new ChildData[] { new ChildData { Data = "Пример1" }, new ChildData { Data = "Пример1" } } } }; var string1 = Newtonsoft.Json.JsonConvert.SerializeObject(list); Yours. List<Recycler> It can be transformed as:var dtoList = list .GroupBy(l => l.Url) .Select(g => new RecyclerData { url = g.Key, childitems = g.Select(d => new ChildData { Data = d.Data }).ToArray() }).ToList(); var m = JsonConvert.SerializeObject(dtoList);

[Serializable] [XmlRoot(Namespace = "", ElementName = "request")] public class Request { [XmlAttribute("guid")] public Guid Id; [XmlElement("Body")] public XmlElement BodyElement; [XmlIgnore] public string Body { get { return this.BodyElement.InnerXml; } set { XmlDocument doc = new XmlDocument(); doc.LoadXml("<goods><good name=\"Товар 1\"/><good name=\"Товар2\"/></goods>"); this.BodyElement = doc.DocumentElement; } } [XmlIgnore] public DateTime? TimeResponce; } ♪ ♪ ♪ ♪Request request = new Request(); request.Id = Guid.NewGuid(); XmlDocument doc = new XmlDocument(); request.Body = "<goods><good name="Товар 1"/><good name="Товар2"/></goods>"; var serializer = new XmlSerializer(typeof(Request)); XmlSerializerNamespaces ns = new XmlSerializerNamespaces(); ns.Add(string.Empty, string.Empty); XmlWriterSettings settings = new XmlWriterSettings() { Indent = false, OmitXmlDeclaration = true, DoNotEscapeUriAttributes = true, }; StringWriter writer = new StringWriter(); using (XmlWriter xw = XmlWriter.Create(writer, settings)) { serializer.Serialize(xw, request, ns); } string value = writer.ToString(); Console.WriteLine(value); StringReader reader = new StringReader(value); var deserialized = (Request)serializer.Deserialize(reader); Console.WriteLine(deserialized.Body); Or, if you'd like,. Request.Body Simple field/execution and transferring to get/set for Request.BodyElement♪

Use it. http://www.newtonsoft.com/json/help/html/T_Newtonsoft_Json_JsonIgnoreAttribute.htm