There are two ways to transfer duplicate keys to form-data:>>> urllib.parse.urlencode((('a',1),('a',2))) 'a=1&a=2' >>> urllib.parse.urlencode({'a':[1,2]},doseq=True) 'a=1&a=2' Similar to multipartresponse = requests.post("http://httpbin.org/post", files=(('a',(None,'1')),('a',(None,2)))) Create a terator (massiv or cortege) in format (имя,(имяфайла, контент)) and pass through the files.Example -----------------------------26945955324554554721766291860 Content-Disposition: form-data; name="profile_showcase[]" 8 I'll be there.("profile_showcase[]",(None, 8))

import cgi import io body="""-----------------------------33331565381703838529424543671 .... """ stream = io.BytesIO(body.encode()) params = {'boundary':b'---------------------------33331565381703838529424543671'} # boundary брать из хидера, на два минуса меньше чем в теле. cgi.parse_multipart(stream, params) Exit{ "weblink_2_title":[""], "real_name":[""], "personaName":["name"], "city":[""], "state":[""], "weblink_2_url":[""], "weblink_1_title":[""], "country":["RU"], "weblink_1_url":[""], "type":[ "profileSave", "profileSave" ], "weblink_3_title":[""], "summary":["dsgsdfg"], "json":["1"], "weblink_3_url":[""], "customURL":["url"], "sessionID":[ "596a2f350ffccdcab68e5408", "596a2f350ffccdcab68e6308" ] } Loss the sequence of answers... It's better for a consistent reading. https://docs.python.org/3/library/cgi.html#cgi.FieldStorage.getlist directly, as is done https://github.com/python/cpython/blob/b745a6143ae79efe00aa46affe5ea31a06b0b532/Lib/cgi.py#L184 No last team.headers = cgi.Message() h.set_type('multipart/form-data; boundary=---------------------------33331565381703838529424543671') fs=cgi.FieldStorage(stream, keep_blank_values=True, headers=headers, environ={'REQUEST_METHOD': 'POST'}) All fields with which to work https://ru.stackoverflow.com/questions/1234354/%D0%9A%D0%B0%D0%BA-%D1%81-%D0%BF%D0%BE%D0%BC%D0%BE%D1%89%D1%8C%D1%8E-post-%D0%B7%D0%B0%D0%BF%D1%80%D0%BE%D1%81%D0%B0-%D1%87%D0%B5%D1%80%D0%B5%D0%B7-requests-%D0%BF%D0%B5%D1%80%D0%B5%D0%B4%D0%B0%D1%82%D1%8C-multipart-form-data-%D1%82%D0%B0%D0%BA-%D1%87%D1%82%D0%BE%D0%B1 received sofiles = [(field.name,(field.filename,field.value)) for field in fs.value] Reply to this question:dict(files)

The question is over. The problem was the banal error in pointing the whole way to the windows file.

On Pythonany where you can build folders in the deposit. Web > Code♪I advise you to launch teams in the consoles. os.getcwd() and os.listdir()to determine which environment you are in.

Look for:Look at the browser developer's tools, what's the online request?Do it. echo $body♪ echo $text

You have in the method, after describing the input parameter, no closing brackets.

So you won't be able to remove the parameters from the river. Type of content multipart/form-data It is necessary to swap the body of the river. I mean, if you're trying to get parameters with help. https://docs.oracle.com/javaee/6/api/javax/servlet/ServletRequest.html#getParameter(java.lang.String) :Returns the value of the request parameter as String or nullif There is no parameter. Request parameters - additional information, requested. For HTTP-servitudes the parameters are contained The line of the request or the body of the request where the forms are located.You get it. null Because the body of the rivervest has a different format, and the above method works if the body of the rivervest has a format. application/x-www-form-urlencoded♪ More detailed information https://developer.mozilla.org/en-US/docs/Web/HTTP/Methods/POST :HTTP POST sends data to the server. Type of request body Reference Content-Type♪Variance PUT and POST is that PUT Yes imputable: challenge one or more times in a row has the same (which is not a side effect) with a consistent identical POST may have additional effects, e.g. transmit the same data several times.Request POST Normally through the HTML form and results in change on the server. In this case, the type of contents shall be selected by means Attribution of the appropriate line enctype component <form> or attribution formenctype elements <input> or <button>:application/x-www-form-urlencoded: keys and values coded in boxes with a key separated by a symbol &, c = between the key and the value. Not alphanumeric symbols in both keys and values coded as a percentage: this type is not suitable to be used with dual data (together use this multipart/form-data); multipart/form-data; text/plain♪To be able to remove the parameters and parts of the files from the riverbank, you can use the anotation. https://docs.oracle.com/javaee/7/api/javax/servlet/annotation/MultipartConfig.html : Annotations which may be placed in class Servletindicating that the specimen of the servitude are awaiting requests corresponding to the type MIME with multipart/form-data♪Annotated with aid MultipartConfigwhich may be extracted Components Part Request multipart/form-data♪ getPart() or getParts()♪You can also read the annotations. https://docs.oracle.com/javaee/6/tutorial/doc/gmhal.html ♪ Which can also be found https://docs.oracle.com/javaee/6/tutorial/doc/glraq.html use of this annotation.

If the heading is self-contained Content-Type♪ boundary No bail will be placed.

PHP PAN 5.5Before this version, CURL files need to be transmitted @ on the way of the file (as is done in naive cURL). In your case:$post_data = array("file1" => '@' . dirname(__FILE__) . $path); PHP grad= 5.5In version 5.5, the class was introduced. http://fi2.php.net/manual/en/class.curlfile.php for downloading files and additive approach @ was declared as Deprecated (and removed to PHP 7.0).Now that the files are downloaded with curl, it looks like:$file1 = new CurlFile(dirname(__FILE__) . $path, 'image/jpg'); $post_data = array("file1" => $file1); Details https://wiki.php.net/rfc/curl-file-upload and http://www.php.net/curl_setopt ♪In the versions PHP 5.5 ♪ 5.6 You can still use an old approach. @but the parameter should be clearly indicated CURLOPT_SAFE_UPLOAD:curl_setopt($ch, CURLOPT_SAFE_UPLOAD, true);

The task came out in the most unexpected way.To send JSON format multipart/mixed (this is the way the file is sent + JSON) JSON and send a second file in format data.json

The decision was trivial, but not obvious. As a result of many experiments and research into HTTP queries, I found the only difference between working and non-working requests. The difference is only in the 4th byte: the name of the file. COMMITMENTS support expansion. The API is ignoring Content-Type: image/png and is fully successful in processing the request without it if the extension is indicated (in addition).png in the name of the file filename♪So this code doesn't work:requests.post(upload_url, files={ 'file': BytesIO('<binary file content>') }) This is being processed successfully:requests.post(upload_url, files={ 'file': ('file.png', BytesIO('<binary file content>'), 'image/png') }) Like this simple version that is not available in GAE:requests.post(upload_url, files={ 'file': open('/path/to/image.png', 'rb') }) Both. StringIO and StringIO Equally suitable for this task. Like I said, Content-Type It doesn't matter, it can be. multipart/form-data♪

Anyway, I moved from SoapUI to Postman, it's much easier and easier.

base64 is the conversion of the bytes to characters ASCII. It is not recommended that you use base64 as it adds more weight to the peticion. For example the simple character hola which are 4 bytes converted to base64 make 8 bytes(Hello in base64 is aG9sYQ==) and as you just said it will be an android application that will send the data, you would be consuming more internet data without need to users.Another thing to consider is that base64 has to be decoded on the server by adding this more process. If you send a +10MB file you would have to first: Convert to base64 to the device: something that is very slow by itself.Send the data to the server: slow and heavy by the amount of data convertedDecode them on the server: slow and unnecessary process.In the case of multipart, this is part of the HTTP protocol while base64 is not. Although it does not compress them it ensures compatibility with all http servers and sends any file type. Advantages:Support on all HTTP serversDo not add more weight to file upload computingAny file can be sent.

Follow this example, it will help you, look at the foreach fileHeaders[HttpPost, Route("api/upload")] public async Task<IHttpActionResult> Upload() { if (!Request.Content.IsMimeMultipartContent()) throw new HttpResponseException(HttpStatusCode.UnsupportedMediaType); var provider = new MultipartMemoryStreamProvider(); await Request.Content.ReadAsMultipartAsync(provider); foreach (var file in provider.Contents) { var filename = file.Headers.ContentDisposition.FileName.Trim('\"'); var buffer = await file.ReadAsByteArrayAsync(); //Do whatever you want with filename and its binaray data. } return Ok(); }

1) Can a form be inserted into another form? Me. I explain. I have a form called "anadir" where I want to add another form called "subir_archivos" because I want the click "Save", previously selecting the desired images, send the details of the form "add".Power can be. What you can't do is send the data from both forms at the same time making a submit because a submit redirects the page and you can't redirect a page 2 times at the same time.To be able to send both data together you have to be on the same form or send them separately using ajax.(2) Just let me select an image, can you choose several for Get them up? Could several images be uploaded?Uses attribute attribute multiple in the input[type=file]:<input name="uploadedfile" type="file" multiple="multiple"/>

$_POST is obtained automatically without the need to read php://input. It is enough to comment/remove the first line.// $_POST = file_get_contents("php://input"); $documento = $_POST['pqr_documento']; echo 'RESP DATA: ' . $documento; Normally file_get_contents("php://input") is used to obtain raw data from POST peticion (request body) when sent such as, for example, a JSON for would return a string with the body of the complete petition (in this case encoded as multipart/form-dataThat you should decode.