That's how you can find a list of processes that's missing your list. String.contains() You're doing a file transfer. Naturally, we need to create a flow. new Tread or new Runnable in which a leaf is requested with some frequency.public class Main { public static void main(String[] args) throws IOException { try { String line; Process p = Runtime.getRuntime().exec("tasklist"); BufferedReader input = new BufferedReader(new InputStreamReader(p.getInputStream())); while ((line = input.readLine()) != null) { System.out.println(line); //<-- Parse data here. } input.close(); } catch (Exception err) { err.printStackTrace(); } } }

Create. viewmake it black and make it transparent. Then add it. view ♪ window♪UIView *myView = [UIView alloc] initWithFrame:yourFrame]; myView.backgroundColor = [UIColor blackColor]; myView.alpha = 0.2f; UIWindow *currentWindow = [UIApplication sharedApplication].keyWindow; [currentWindow addSubview:myView]; It doesn't make sense for this wine to find and click the library.

Deserylization is likely to work normally. And here are the files you want to access on the Androyd, you need to put in the asset folder (if memory doesn't change at one level with java folder). Read the file there, you can read:context.getResources().getAssets().open("testSerial.gbw")

That's the work. cmd.exe♪cmd.exe sends the text to the intake flow fast, and Ctrl+Z only if other symbols were not inserted before the entry.This can be ascertained by rewriting the programme as follows:#include <iostream> #include <string> int main() { std::string s; while (std::cin >> s) for (int b : s) std::cout << std::hex << b << ' '; } If something was introduced. ^Zit's interpreted as \x1a (sighs) https://en.wikipedia.org/wiki/Substitute_character and everything that has been introduced in this line is ignored:> test.exe 1^Z23 4 31 1a 34 It's a default. std::istream No. \1a I don't know.If you don't, ^Z Nothing to enter, the flow closes, and the following symbols in the line ignore:> test.exe 123 31 32 33 ^Z456 >

PrintWriter Not exactly a normal class if we look at the documentation for the class, we'll see the following:Methods in this class never throw I/O exceptions, although some of its constructors may. The client may inquire as to whether any errors have occurred by invoking {@link #checkError checkError()}.I mean, he's promulgating all the intake errors.

Here's your dead cycle.while (true) { displayDetails(currentItem); } You're hoping you'll get out of it, but it doesn't seem like an exception. And it doesn't seem the most likely because the variable value currentItem There is no change in the cycle.

The current folder has an annex, so it's impossible to move it. At least that's what comes first.

Started Studio on behalf of the administrator and there's no mistake.

io.popen gives an interface to the system posix function popen, yes, it can only work one way. In your case, you don't need to write anything in ps. If you open it for reading, she'll read it. But I understand. ps You only have an example...POSIX has only one way to deal with both file descriptors of the process. Setting up a pair of sockets, linking one of these compounds to file descriptors 0 and 1dup2) Follow-up fork and the daughter-in-law cause a proper program.In Lua, there is no evidence of such funds. So the direct answer to your question is to get stdin and stdout at the same time impossible. Only the redirection of the programme to the file and the subsequent reading of the file can be seen from the decisions. Or an entry for the program is written in advance and submitted to the entrance. And we can still experiment with known channels. mkfifo To create a nameable channel in the file system to send it to the program or the recording from the program to redirect it into it and to lua to open this channel as a regular file and try writing/reading.

In SerialPort, there's a DataReceived event that occurs when data from a consistent port are produced. Asynchronous port communication in 2 (Task) can be used https://msdn.microsoft.com/ru-ru/library/dd449174 and https://msdn.microsoft.com/ru-ru/library/system.threading.cancellationtokensource(v=vs.110).aspx ♪ Order of work:TaskCompletionSource and CancellationTokenSource shall be established upon request to the portFor CancellationTokenSource via Token.Register() the revocation processor shall be added and time shall be displayed.The data are recorded at the port.The task is expected to be completed in the meantime for the TaskCompletionSource.When we get the data from the port, we try to process them.If successful, we will complete the task through the TaskCompletionSource.TrySetResult()In case of error, the task is completed through the TaskCompletionSource.TrySetException()In the case of a timemaut, Cancellation TokenSource will work.Example of class with the above-mentioned conduct:class ModemConnection : IDisposable { private readonly SerialPort _serialPort; private bool _disposed; private TaskCompletionSource&lt;Frame&gt; _taskCompletionSource = new TaskCompletionSource&lt;Frame&gt;(); public TimeSpan Timeout { get; set; } public ModemConnection(string portName, int baudRate, Parity parity, int dataBits, StopBits stopBits) { _serialPort = new SerialPort(portName, baudRate, parity, dataBits, stopBits); _serialPort.DataReceived += _serialPort_DataReceived; } private async Task&lt;Frame&gt; SendFrame(Frame frame) { var cts = new CancellationTokenSource(); _taskCompletionSource = new TaskCompletionSource&lt;Frame&gt;(); cts.Token.Register(tcs =&gt; ((TaskCompletionSource&lt;Frame&gt;)tcs).TrySetCanceled(), _taskCompletionSource, false); cts.CancelAfter(Timeout); var bw = new BinaryWriter(_serialPort.BaseStream, Encoding.ASCII, true); frame.Write(bw); bw.Flush(); Task.Run(() =&gt; OnOnFrameSent(frame)); return await _taskCompletionSource.Task.ConfigureAwait(false); } private void _serialPort_DataReceived(object sender, SerialDataReceivedEventArgs e) { try { var r = new BinaryReader(new BufferedStream(_serialPort.BaseStream), Encoding.ASCII, true); var frame = new Frame(); frame.Read(r); _taskCompletionSource?.TrySetResult(frame); Task.Run(() =&gt; OnOnFrameReceived(frame)); } catch (Exception ex) { _taskCompletionSource?.TrySetException(ex); } } public event EventHandler&lt;Frame&gt; FrameReceived; protected virtual void OnOnFrameReceived(Frame e) { FrameReceived?.Invoke(this, e); } public event EventHandler&lt;Frame&gt; FrameSent; protected virtual void OnOnFrameSent(Frame e) { FrameSent?.Invoke(this, e); } public void Open() { if (_serialPort.IsOpen) return; _serialPort.Open(); } public void Dispose() { if (_disposed) return; _disposed = true; _serialPort.Dispose(); } }

Try writingr.flush at the end, it's likely that there's a leftover.

Instead of https://msdn.microsoft.com/en-us/library/system.runtime.interopservices.marshalasattribute.sizeconst(v=vs.100).aspx , indicating the constant number of elements in the mass, you should use https://msdn.microsoft.com/en-us/library/system.runtime.interopservices.marshalasattribute.sizeparamindex(v=vs.100).aspx indicating the index of the size of the membership of the structure (in your case, countChars ♪ 0)

The repetitive symbol is not removed because the method StreamReader.Read() Moves the position of the following strime: FileStream♪ You have one. StreamReader Every time it's new. If the first symbol is to be removed, the starting point of each cycle is to be returned to the beginning:FileStream fs = new FileStream(@"C:\ab\1.txt", FileMode.Open); for (int x = 0; x < fs.Length; x++) { fs.Seek(0, SeekOrigin.Begin); Console.WriteLine(new StreamReader(fs).Read()); } Why is the first symbol on the irration x=0, I think, understand?Now, why are you going on? StreamReader has an internal buffer -- 1024 Byte default. Accordingly, first challenge StreamReader.Read() The buffer shall be filled and the position of the following strime shall be moved. If the size of the lower buoy is less than 1024 bayts, the first challenge StreamReader.Read() all contents will be read and the position will be at the end. Accordingly, the following is being returned -1 because the strime is over. Obviously, this is your case. It is possible, for example:FileStream fs = new FileStream(@"C:\ab\1.txt", FileMode.Open); Console.WriteLine("Length " + fs.Length); for (int x = 0; x < fs.Length; x++) { Console.WriteLine(new StreamReader(fs).Read() + " - new pos " + fs.Position); } Such behaviour could be eliminated, indicating the size of the buffer at 1:new StreamReader(fs, Encoding.UTF8, true, 1) But... StreamReader has a built-in minimum size of the buffer in 128, so it will not help:P.S. Don't forget to turn the strings in. using!

Mistakes:(1) for (Message message : list) { if (!isLoggedIn) { lastWriteFuture = ch.writeAndFlush("loginpassword"); } //if login is success, I must loop through all data in list and send other data to server lastWriteFuture = ch.writeAndFlush(message.getDataString); } You'll have the copying done as many times as you have messages to send.(2) lastWriteFuture = ch.writeAndFlush(message.getDataString);It doesn't make any sense, because at this point you're always not authorised.You're in the hendler, like an example, to a class that triggered a conject. After receiving a response, the hendler causes this class, and he's already a co-contained nect, if the authorisation is successful.BtwI'd like to read the Future/Promise.

I don't know what your problem is. Let's go on the items:(1) The flow will certainly not help you, because (wam correctly noted in the commentary) there will be a bottleneck of entry/out, not CPU, and you will only slow down the work.(2) If the challenge is that you need to deal with each program launch. all over again The file that is very large, so the speed is important, you should read this: http://nadeausoftware.com/articles/2008/02/java_tip_how_read_files_quickly (3) If it seems to me that this is your case, the challenge is that your program has to hang and constantly read and process new data that come into the file, it's very simple: read fast and process the readings; if it's over, we're gonna go down for a little while, and then we're gonna read the new data, and then we're going to read it. 50-75 lines a second -- that's a little bit, no special predatory. Something like:... String line; while (true) { while ((line = in.readLine()) != null) { // Обработка строки ... } // Вышли из цикла, значит данные в файле пока закончились. // Засыпаем на секунду, а затем пробуем снова. Thread.sleep(1000); } ...

If you use this Hyde, it'll be the bottom. https://wiki.osdev.org/Serial_Ports ♪It should be accompanied by the current terminal discipline (echo, translate CR/NL into editing of the entry (in the sense of backspace, etc.) and the buffer to which it will put the incoming symbols.Sam. getchar() I'll take the symbols from this buffer.In fact, you need to make a policy decision, you're in your D.O.'s work on interruptions. read_serial() You need to connect to the IRQ processor or synchronized. If synchronized, getchar() to call read_serial() If there's no one in the buffer.Issued read_serial() He'll pick up the motto and put as many symbols as he can in the buffer, say, given the time latched at the current speed of the motto.Well, read_serial() It is worth a few summarizing, for example, the reference address of the Deviceaise and M.B. registers. One program can then read a few different devices.Well, something like that.

I don't know. srcds.batbut I'll show you two how to get the data.I'm running a battery for the test. 1.batwhich starts a python with values ranging from 0 to 4 times per second:@echo off echo arg1=%1 python -c "import time;[(print(i), time.sleep(1)) for i in range(5)]" Mode 1: stdout during the programme:import subprocess srcds = subprocess.Popen(r"1.bat -console", stdout=subprocess.PIPE, shell=False, universal_newlines=True) for line in srcds.stdout: line = line.rstrip() print(line) Mode 2: We await the end of the programme and consider the outcome:import subprocess srcds = subprocess.Popen(r"1.bat -console", stdout=subprocess.PIPE, shell=False, universal_newlines=True) srcds.wait() out, err = srcds.communicate() print(out) Result:arg1=-console 0 1 2 3 4

Problem solved.The flow is incorrect when using the relative route of the facility:File ("./file.txt") Everything has become correct in applying an absolute route to the file.

Coding CP1251 ♪ UTF-8 ♪ UTF-32 - different. And your console only uses one. First, you need to know your coding of the console, and then in the program, you'll have to carpet in it.Try to convert. https://www.cplusplus.com/reference/locale/wstring_convert/ Then you can make it look like UTF-8♪# include <iostream> # include <codecvt> # include <locale> using std::cout; using std :: endl; int main(){ char symbol_ch = 'Q'; cout &lt;&lt; symbol_ch &lt;&lt; endl; std::wstring_convert&lt;std::codecvt_utf8&lt;wchar_t&gt;,wchar_t&gt; cw; cout &lt;&lt; cw.to_bytes(L"Алло") &lt;&lt; endl; std::wstring_convert&lt;std::codecvt_utf8&lt;char32_t&gt;,char32_t&gt; cv; cout &lt;&lt; cv.to_bytes(U"zß水") &lt;&lt; endl; } Q Алло zß水

Documents https://pkg.go.dev/errors#New and readNew returns an error that formats as the given text. Each call to New returns a distinct error value even if the text is identical.Every challenge New to a mistake returns the new meaning of error even if the text coincides.And since it's returning a new object, they're not equal.